It’s no doubt, you must have played Tic Tac Toe in your school days and every one of us loves to play the game. You will be surprised to know that the game of Tic Tac Toe is known to exist since ancient Egypt times.
With this Python project by SGN Designer, we are going to build an interactive game of Tic Tac Toe where we’ll learn new things along the way.
What is Tic Tac Toe?
Tic Tac Toe is one of the most played games and is the best time killer game that you can play anywhere with just a pen and paper. If you don’t know how to play this game don’t worry let us first understand that.
The game is played by two individuals. First, we draw a board with a 3×3 square grid. The first player chooses ‘X’ and draws it on any of the square grid, then it’s the chance of the second player to draw ‘O’ on the available spaces. Like this, the players draw ‘X’ and ‘O’ alternatively on the empty spaces until a player succeeds in drawing 3 consecutive marks either in the horizontal, vertical or diagonal way. Then the player wins the game otherwise the game draws when all spots are filled.
Python Tic Tac Toe – Project Details
The interesting Python project will be build using the pygame library. We will be explaining all the pygame object methods that are used in this project. Pygame is a great library that will allow us to create the window and draw images and shapes on the window. This way we will capture mouse coordinates and identify the block where we need to mark ‘X’ or ‘O’. Then we will check if the user wins the game or not.
Download Tic Tac Toe Project code
Please download the full source code of tic tac toe project: Tic Tac Toe Python Project
pip install pygame
Steps to Build a Python Tic Tac Toe Game
First, let’s check the steps to build Tic Tac Toe program in Python:
- Create the display window for our game.
- Draw the grid on the canvas where we will play Tic Tac Toe.
- Draw the status bar below the canvas to show which player’s turn is it and who wins the game.
- When someone wins the game or the game is a draw then we reset the game.
We need to run our game inside an infinite loop. It will continuously look for events and when a user presses the mouse button on the grid we will first get the X and Y coordinates of the mouse. Then we will check which square the user has clicked. Then we will draw the appropriate ‘X’ or ‘O’ image on the canvas. So that is basically what we will do in this Python project idea.
1. Initializing game components
So let’s start by importing the pygame library and the time library because we will use the time.sleep() method to pause game at certain positions. Then we initialize all the global variables that we will use in our Tic Tac Toe game.
import pygame as pg,sys from pygame.locals import * import time #initialize global variables XO = 'x' winner = None draw = False width = 400 height = 400 white = (255, 255, 255) line_color = (10,10,10) #TicTacToe 3x3 board TTT = [[None]*3,[None]*3,[None]*3]
Here, the TTT is the main 3×3 Tic Tac Toe board and at first, it will have 9 None values. The height and width of the canvas where we will play the game is 400×400.
2. Initializing Pygame window
We use the pygame to create a new window where we’ll play our Tic Tac Toe game. So we initialize the pygame with pg.init() method and the window display is set with a width of 400 and a height of 500. We have reserved 100-pixel space for displaying the status of the game.
The pg.display.set_mode() initializes the display and we reference it with the screen variable. This screen variable will be used whenever we want to draw something on the display.
The pg.display.set_caption method is used to set a name that will appear at the top of the display window.
#initializing pygame window pg.init() fps = 30 CLOCK = pg.time.Clock() screen = pg.display.set_mode((width, height+100),0,32) pg.display.set_caption("Tic Tac Toe")
3. Load and transform images
The Python project uses many images like the opening image that will display when the game starts or resets. The X and O images that we will draw when the user clicks on the grid. We load all the images and resize them so that they will fit easily in our window.
#loading the images opening = pg.image.load('tic tac opening.png') x_img = pg.image.load('x.png') o_img = pg.image.load('o.png') #resizing images x_img = pg.transform.scale(x_img, (80,80)) o_img = pg.transform.scale(o_img, (80,80)) opening = pg.transform.scale(opening, (width, height+100))
4. Define the functions
Now we create a function that will start the game. We will also use this function when we want to restart the game. In pygame, the blit() function is used on the surface to draw an image on top of another image.
So we draw the opening image and after drawing, we always need to update the display with pg.display.update(). When the opening image is drawn, we wait for 1 second using time.sleep(1) and fill the screen with white colour.
Next, we draw 2 vertical and horizontal lines on the white background to make the 3×3 grid. In the end, we call the draw_status() function
def game_opening(): screen.blit(opening,(0,0)) pg.display.update() time.sleep(1) screen.fill(white) # Drawing vertical lines pg.draw.line(screen,line_color,(width/3,0),(width/3, height),7) pg.draw.line(screen,line_color,(width/3*2,0),(width/3*2, height),7) # Drawing horizontal lines pg.draw.line(screen,line_color,(0,height/3),(width, height/3),7) pg.draw.line(screen,line_color,(0,height/3*2),(width, height/3*2),7) draw_status()
The draw_status() function draws a black rectangle where we update the status of the game showing which player’s turn is it and whether the game ends or draws.
def draw_status(): global draw if winner is None: message = XO.upper() + "'s Turn" else: message = winner.upper() + " won!" if draw: message = 'Game Draw!' font = pg.font.Font(None, 30) text = font.render(message, 1, (255, 255, 255)) # copy the rendered message onto the board screen.fill ((0, 0, 0), (0, 400, 500, 100)) text_rect = text.get_rect(center=(width/2, 500-50)) screen.blit(text, text_rect) pg.display.update()
The check_win() function checks the Tic Tac Toe board to see all the marks of ‘X’ and ‘O’. It calculates whether a player has won the game or not. They can either win when the player has marked 3 consecutive marks in a row, column or diagonally. This function is called every time when we draw a mark ‘X’ or ‘O’ on the board.
def check_win(): global TTT, winner,draw # check for winning rows for row in range (0,3): if ((TTT [row] == TTT[row] == TTT[row]) and(TTT [row] is not None)): # this row won winner = TTT[row] pg.draw.line(screen, (250,0,0), (0, (row + 1)*height/3 -height/6),\ (width, (row + 1)*height/3 - height/6 ), 4) break # check for winning columns for col in range (0, 3): if (TTT[col] == TTT[col] == TTT[col]) and (TTT[col] is not None): # this column won winner = TTT[col] #draw winning line pg.draw.line (screen, (250,0,0),((col + 1)* width/3 - width/6, 0),\ ((col + 1)* width/3 - width/6, height), 4) break # check for diagonal winners if (TTT == TTT == TTT) and (TTT is not None): # game won diagonally left to right winner = TTT pg.draw.line (screen, (250,70,70), (50, 50), (350, 350), 4) if (TTT == TTT == TTT) and (TTT is not None): # game won diagonally right to left winner = TTT pg.draw.line (screen, (250,70,70), (350, 50), (50, 350), 4) if(all([all(row) for row in TTT]) and winner is None ): draw = True draw_status()
The drawXO(row, col) function takes the row and column where the mouse is clicked and then it draws the ‘X’ or ‘O’ mark. We calculate the x and y coordinates of the starting point from where we’ll draw the png image of the mark.
def drawXO(row,col): global TTT,XO if row==1: posx = 30 if row==2: posx = width/3 + 30 if row==3: posx = width/3*2 + 30 if col==1: posy = 30 if col==2: posy = height/3 + 30 if col==3: posy = height/3*2 + 30 TTT[row-1][col-1] = XO if(XO == 'x'): screen.blit(x_img,(posy,posx)) XO= 'o' else: screen.blit(o_img,(posy,posx)) XO= 'x' pg.display.update() #print(posx,posy) #print(TTT)
The userClick() function is triggered every time the user presses the mouse button.
When the user clicks the mouse, we first take the x and y coordinates of where the mouse is clicked on the display window and then if that place is not occupied we draw the ‘XO’ on the canvas. We also check if the player wins or not after drawing ‘XO’ on the board.
def userClick(): #get coordinates of mouse click x,y = pg.mouse.get_pos() #get column of mouse click (1-3) if(x<width/3): col = 1 elif (x<width/3*2): col = 2 elif(x<width): col = 3 else: col = None #get row of mouse click (1-3) if(y<height/3): row = 1 elif (y<height/3*2): row = 2 elif(y<height): row = 3 else: row = None #print(row,col) if(row and col and TTT[row-1][col-1] is None): global XO #draw the x or o on screen drawXO(row,col) check_win()
The last function is the reset_game(). This will restart the game and we also reset all the variables to the beginning of the game.
def reset_game(): global TTT, winner,XO, draw time.sleep(3) XO = 'x' draw = False game_opening() winner=None TTT = [[None]*3,[None]*3,[None]*3]
5. Run the tic tac toe game forever
To start the game, we will call the game_opening() function. Then, we run an infinite loop and continuously check for any event made by the user. If the user presses mouse button, the MOUSEBUTTONDOWN event will be captured and then we will trigger the userClick() function. Then if the user wins or the game draws, we reset the game by calling reset_game() function. We update the display in each iteration and we have set the frames per second to 30.
game_opening() # run the game loop forever while(True): for event in pg.event.get(): if event.type == QUIT: pg.quit() sys.exit() elif event.type == MOUSEBUTTONDOWN: # the user clicked; place an X or O userClick() if(winner or draw): reset_game() pg.display.update() CLOCK.tick(fps)
Hooray! The game is complete and ready to play. Save the source code with the tictactoe.py file name and run the file.
With this project in Python, we have successfully made the Tic Tac Toe game. We used the popular pygame library for rendering graphics on a display window. We learned how to capture events from the keyboard or mouse and trigger a function when the mouse button is pressed. This way we can calculate mouse position, draw X or O on the display and check if the player wins the game or not. I hope you enjoyed building the game.
1 thought on “Tic Tac Toe – Develop a Game in Python”
This is really a very good game : This is what we played the most during school time, really reminded me of school days brother really thank you 🤗🤗